Originally Posted by
uberbandgeek6 I'm not sure if I'm approaching this problem correctly:
A single playing card is drawn at random from each of six well-shuffled decks of playing cards. Let A be the event that all six cards drawn are different.
(a) Find P(A).
(b) Find the probability that at least tow of the drawn cards match.
I think for (b) is will simply be 1 - P(A), but I need to find P(A) first. Here is the way I think I should solve it: The first deck will always be a "different" card, so it has probability of 1. The second deck has a probability of 51/52 of being a different card. The third would be 50/52, etc. So it comes down to P(A) = 52*51*...*47 / (52^6). Is this correct?