You question is really not clear as to what you mean.
If you want to know how ways to arrange 1,2,3,4,5, &6, then that is (6!)=(6)(5)...(2)(1)=720.
If your question is something else, please explain in some detail.
We are having a debate in work,found your page and taught you might be
>able to help solve the debate, We have a small lottery in work. There are
>six numbers 1,2,3,4,5,6, We were wondering how many different combinations
>there would be with these numbers. It's a long time since any of us did
>probability
>
>kind Regards
>
>Mark
Hello, Mark!
We have a small lottery in work.
There are six numbers 1,2,3,4,5,6.
We were wondering how many different combinations there would be.
Since you didn't give us the exact rules of your lottery,
. . I'll have to guess what they are.
One possible lottery:
[1] We pick a six-digit number using {1,2,3,4,5,6}.
. . .Digits may be repeated.
[2] One of the six-digit numbers is randomly chosen as the winner.
In this scenario, there are: possible six-digit numbers.
Another possible lottery:
[1] We pick a six-digit number using {1,2,3,4,5,6}.
. . .Digits may not be repeated.
[2] One of the six-digits number is randomly chosen as the winner.
Then there are: . possible six-digit numbers.