# Math Help - probability and lottery questions help

1. ## probability and lottery questions help

Please help showing me the working out would be great as i need to learn how to do them

The cost of a standard 12 game card (where you select 12 combinations of six numbers) is $4.05c$8 million is spent by the public each week on lotteries
60% of the takings are returned to winners
The government share is 36%
The lottery organisation receives 4%

1. What is the cost of 1 game?
2. How many games on average are played each week?
3. Show that the probability of winning first division (6 numbers correct) in any one game is 1/8145060
4.What is the probability of not winning first devision?
5. If you buy a 12 game card, what is the probability of winning with one of the games?
6. How many first division winners are expected each week, assuming each player buys only one standard 12 game card?

2. Originally Posted by jamiebrayden
Please help showing me the working out would be great as i need to learn how to do them

The cost of a standard 12 game card (where you select 12 combinations of six numbers) is $4.05c$8 million is spent by the public each week on lotteries
60% of the takings are returned to winners
The government share is 36%
The lottery organisation receives 4%

1. What is the cost of 1 game?
2. How many games on average are played each week?
3. Show that the probability of winning first division (6 numbers correct) in any one game is 1/8145060
4.What is the probability of not winning first devision?
5. If you buy a 12 game card, what is the probability of winning with one of the games?
6. How many first division winners are expected each week, assuming each player buys only one standard 12 game card?

hm...

1) where is problem? if you have 12 combinations and they cost $4.05c just divide that price with number of combinations and youl get how much does it cost one 2) when you have price of one game divide that with that$8M so you have number of how many by the week is played

3) i assume that 1/8145060 (0.00001227738 % ) should be chance to win in percentages (for any combination) so do you know, if you have 12 combinations what is percentage of do get one of 12 ? ( (1/12) * 100 = 8.3333333 %) .... do you understand how to answer this ?

4) same as the third question with different approach

5) and 6) are going same way ...

show what have you done