Originally Posted by

**cyt91** Hi, should I use binomial distribution to solve the following question? (a) to be specific. I managed to solve (b)

Research shows that 40% of Singaporeans prefer tea, 35% prefer coffee and the rest prefer milk. 9 persons were randomly chosen. Find the probability that

(a) the same number of people prefer each type of drink. Ans:0.07203

(b) more people prefer tea to the other drinks. Ans:0.2666

T~B(9,0.4)

C~B(9,0.35)

M~B(9,0.25)

P(T=3) x P(C=3) x P(M=3)

= {9C3(0.4)^3 x (0.6)^6} x {9C3(0.35)^3 x (0.65)^6} x {9C3(0.25)^3 x (0.75)^6}

= 0.01591

But the answer given is 0.07203. Spot any mistakes?

Thanks for your help.