Probability math problem

**Zora** · August 30th 2010, 09:32 PM

Type O: 44%

Type A: 42%

Type B: 10%

Type AB: 4%

What is the probability that the first two people in the line up have the same type of blood? Express your answer to the nearest hundredth of one percent.

What is the probability that none of the first five people in the line up have type AB blood? Express your answer to the nearest hundredth of one percent.

**Soroban** · August 30th 2010, 10:45 PM

Hello, Zora!

. . $\begin{array}{cc}\text{Type O:} & 44\% \\ \text{Type A:} & 42\% \\ \text{Type B:} & 10\% \\ \text{Type AB:} & 4\% \end{array}$

What is the probability that the first 2 people in line have the same type of blood?
Express your answer to the nearest hundredth of one percent.

There are four cases:

$\begin{array}{cccccc} \text{Both type O:} & (0.44)^2 &=& 0.1936 \\ \text{Both type A:} & (0.42)^2 &=& 0.1762 \\ \text{Both type B:} & (0.10)^2 &=& 0.0100 \\ \text{Both type AB:} & (0.04)^2 &=& 0.0016 \\ \hline & \text{Total: } && 0.3816 \end{array}$

Therefore: . $P(\text{2, same type}) \:=\:38.16\%$

What is the probability that none of the first 5 people in line have type AB blood?
Express your answer to the nearest hundredth of one percent.

We have: . $P(\text{not AB}) \:=\: 96\% \:=\:0.96$

$P(\text{5, not AB}) \:=\:(0.96)^5 \:=\:0.815372698$

Therefore: . $P(\text{5, not AB}) \;=\;82.54\%$

**CaptainBlack** · August 30th 2010, 11:32 PM

Originally Posted by Zora

Type O: 44%

Type A: 42%

Type B: 10%

Type AB: 4%

What is the probability that the first two people in the line up have the same type of blood? Express your answer to the nearest hundredth of one percent.

What is the probability that none of the first five people in the line up have type AB blood? Express your answer to the nearest hundredth of one percent.

You might ask if they want answers to the nearest hundredth of one percent why they can't be bothered to give the proportions with each blood group to the same precision

CB

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