# Thread: Normal Distribution

1. ## Normal Distribution

I cant figure this out have been working on it for hours. Confused on part b.

1. Because of water shortages during a drought in a Canadian city, watering of lawns and gardens was permitted only from 06:00 to 09:00 and from 19:00 to 22:00. The peak consumption, as a percentage of total system capacity, was recorded each watering period for a week in July. Assume that the water consumption was normally distributed.And there is only 7 days but 14 watering periods so two watering periods a day.

88, 95, 65, 94, 67, 94, 75,
93, 77, 100, 85, 100, 85, 100

a. Find the mean and the standard deviation.
µ = 87, σ = 11

b .Water pressure problems occur in the system after 99% capacity is reached. On what percentage of the days were there problems?

2. Originally Posted by Zora

b .Water pressure problems occur in the system after 99% capacity is reached. On what percentage of the days were there problems?
It seems to me to be as simple as $\frac{3}{14} \times 100 =\dots$

3. No I doubt it because it is worth 3 marks somethign so simple wouldn't be worth so much.

4. Originally Posted by pickslides
It seems to me to be as simple as $\frac{3}{14} \times 100 =\dots$
There are only seven days not fourteen

CB

5. Originally Posted by Zora
No I doubt it because it is worth 3 marks somethign so simple wouldn't be worth so much.
Is this assessed work? Does it contribute to you final grade?

CB

6. Originally Posted by Zora
No I doubt it because it is worth 3 marks somethign so simple wouldn't be worth so much.
Then go back and look at your notes, because that is (when corrected, or using the answer in the other thread that you chose to ignore) the answer to the question as asked.

CB