So its time! The Final Exam is but two days away!

I am studying old math tests... but, alas, I did not correct my errors!

There are 4 problems that i did and I answered incorrectly. I will give my work... Ive looked over them a couple times and (since im rusty from going over them a half year ago) Im not 100% sure what the real thing is.

1) A basketball team of 10 players - 4guards, 3forwards, 3centers - is electing two captains. Find the probability that a guard And a center will be elected

so.... 4Guards

3Forwards

3Centers

with 10 in total

i did {(4C1) X (6C0) / 10C1 } X {(3C1) X (7C0) / 10C1}

(so it was the Probability for Guards times the probability for Centers )

and it = .12

where did i go wrong? :confused:

2) There are 18 juniors and 10 seniors in a class. If 6 of the seniors are males and 12 of the juniors are females, find the probability of selecting a senior or a male

P(senior) + P(male) - P(Senior and Male)

so we have 18 juniors with 6M and 12F

and 10 seniors with 6males and 4 females

(10/18) + (12/28) - (16/10) = .384126

3) Find the probability that three cards drawn from a dec without replacement contain at least two hearts

a deck of card has 52 cards and 13 hearts

I had 13C2 X 39C1 / 52C3

Im guessing though, that this one, it was supposed to be

3C2 X (13/52)^2 X (39/52)^1 since it is WITHOUT replacement, right?

4) How many ways can a jury of 6men and 6women be selected from 12men and 12 women

I had 12C6 + 12C6 = 1848

but im guessing it should have been 12C6 X 12C6 correct?

Thank you very very much for your time!