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**Jskid** A talent show judge has 6 semi finalists. The judge thinks that none of them have any talent and will randomly select the 3 winners. Suppose that in fact, there are 2 semi finalists that are talented and are equally talented. What is the probability that both will be selected in the top 3? The answer is $\displaystyle \frac{24}{120}$

I did 6C2 because there are 6 people and 2 need to be picked from them, divided by 6C3 because that's the total possible way 3 people from the 6 can be selected. So $\displaystyle \frac{6C2}{6C3}=\frac{3}{4}$