If you mean there is probability of not getting an even on either draw.
Then yes, that is correct.
Given a set of numbers from 1 to 10, if two numbers are to be selected from these 10 numbers with replacement, what is the probability that at least one of them is even?
Is my process correct?-
Chance of picking even on first= 1/2 and second is 1/2 so chance NOT picking would be 1/2 and 1/2. So, 1-(1/4) would give our answer.
Is this the correct process when you see the "at least one" in a probability question?