Hello, hello there!

This is a "combination" problem.a) How many possible 3-card poker hands are there from a standard deck of 52 cards?

There are: .C(52,3) .= .52!/(3!49!) .= .22,100 possible poker hands.

Assuming that an Ace can be "high" or "low", the sequence can run from A-2-3 to Q-K-A.b) The highest hand is a straight flush,

three cards in order from the same suit (i.e. 7-8-9 of hearts).

What is the probability of getting a straight flush?

. . There are 12 possible sequences.

Since there are 4 suits, there are: .4 × 12 .= .48 possible straight flushes.

Therefore: .P(straight flush) .= .48/22,100 .= .12/5525