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Math Help - Simple GCSE Binomial Distribution Question

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    Simple GCSE Binomial Distribution Question

    Hello posters, i am just wondering if you could help me out here; I have my GCSE exam in two days and having left school without a mark scheme - please could you just tell me the answer to question below so I can see whether i got it right. Thanks in advance.

    The probability that a bag of rice weighs less than 260g is 0.3.

    Four Bags are chosen at random

    What is the probability that exactly one bad weighs less than 260g?
    You may use p⁴ + 4pq + 6pq + 4pq + q⁴
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    Quote Originally Posted by dan9408 View Post
    Hello posters, i am just wondering if you could help me out here; I have my GCSE exam in two days and having left school without a mark scheme - please could you just tell me the answer to question below so I can see whether i got it right. Thanks in advance.

    The probability that a bag of rice weighs less than 260g is 0.3.

    Four Bags are chosen at random

    What is the probability that exactly one bad weighs less than 260g?
    You may use p⁴ + 4pq + 6pq + 4pq + q⁴
    X ~ Binomial(n = 4, p = 0.3)

    Pr(X = 1) = {4 \choose 1} (0.3)^1 (0.7)^3 = ....
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    Quote Originally Posted by dan9408 View Post
    Hello posters, i am just wondering if you could help me out here; I have my GCSE exam in two days and having left school without a mark scheme - please could you just tell me the answer to question below so I can see whether i got it right. Thanks in advance.

    The probability that a bag of rice weighs less than 260g is 0.3.

    Four Bags are chosen at random

    What is the probability that exactly one bad weighs less than 260g?
    You may use p⁴ + 4pq + 6pq + 4pq + q⁴
    Dear dan9408,

    For the Binomial distribution, b(x;n,\theta)=~^{n}C_{x}\theta^{x}(1-\theta)^{n-x}
    where x:~Number~of~successes
    n:~number~of~trials
    \theta:~probability~of~a~success

    In this case define the success as "a bag of rice weights less than 260g"

    Hope you will be able to continue.
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