Here's the question:

Suppose that a wheel, partitioned into three equal quadrants (labeled 1, 2, and 3), is spun 2 times.

**a) List all the outcomes in the Sample Space.**

Code:

1,1
1,2
1,3
2,1
2,2
2,3
3,1
3,2
3,3

**b) What is the probability that each spin lands on either the number "1" or the number "2"?**

With this question, would I simply be counting the outcomes with only "1's" and "2's" and divided the total number of outcomes? For example, I counted "1,1" "1,2" "2,1" "2,2" = 4 and divide by 9 to get .44

Is this correct?

**c) What is the probability that both spins land on the same number?**

Each number has a .33 probability of being landed on, so I assume I multiply the probability twice to get .1089