A pair of dice are thrown. What is the probability of
i. getting at least one six
ii. getting a total of nine or greater
iii getting an even number and a total of eight?
(i)
P(at least one 6)=1-P(no sixes)
That should be easy enough
(ii)
You can identify the combinations possible that give a total of nine or more
6+3
6+4
6+5
6+6
(4 combinations)
5+4
5+5
5+6
(3 combinations)
4+5
4+6
(2 combis)
3+6
(1 combi)
total 5+4+3+1=15 cominbations, all with a probability of 1/36
Answer: 15/36
(iii)
This is the same principle as part II so you should be able to do it now