Dice and the binomial distribution.

A Die is Biased so that the probability of throwing a 5 is 0.75 and the probabilities of throwing a 1,2,3,4 or 6 are all equal.

i. The Die is thrown three times. Find the probability that the result is a 1 followed by a 5 followed by any even number.

My Attempt: P of 5: 0.75 for 1,2,3,4,6: 0.05

So P( 1 followed by 5 and then even)= 0.05 x .075 x (0.05+0.05+0.05) (adding because of "or")

= 0.0005625

ii. Find the Probability that, out of 10 throws of this die, at least 8 result in a 5.

My attempt: using binomial p = .75 q=.25

n=10

p(x ≥ 8) = p(x=8) + p(x=9) + p(x=10)

= 10C8 (.75)^8 (0.25)^2 + 10C9 (0.75)^9 (0.25)+ 10C10 (0.75)^10 (0.25)^0

iii. The die is thrown 90 times. Using an appropriate approximation, find the probability that a 5 is thrown more than 60 times.

Please solve this one. We have studied binomial and normal Distribution Only :)

Please check my attempts and tell me is it correct? if wrong tell me where did i go wrong. and please give ur advices too. My Exam is on 24th May So need Tips