It would help if you told us why you think these are the answers.

The number of days out of 3 that is rains in a binomial random variable with

distribution B(3, 0.6), for which:

p(n; 3, 0.6) = 3!/(n!(3-n)!) 0.6^n (1-0.6)^{3-n}.

For (1), n=3, and so:

p(3; 3, 0.6) = 0.6^3 ~= 0.216.

For (2), n=2, and so:

p(2; 3, 0.6) = 3 (0.6^2) (0.4) ~= 0.432

RonL