Hi guys....
i dunt realli understand how to do this question:
what is the probability that a triple for a dice..will occur within the first 5 rolls?
also, im not sure if this is Binomal or geometric...
Thanks in advance.
Hi guys....
i dunt realli understand how to do this question:
what is the probability that a triple for a dice..will occur within the first 5 rolls?
also, im not sure if this is Binomal or geometric...
Thanks in advance.
$\displaystyle Pr(\text{triple}) = \frac{6}{6^3} = \frac{1}{36}$ since there are $\displaystyle 6^3$ ways of rolling $\displaystyle 3$ die, and only $\displaystyle 6$ of the outcomes are triples.
The desired probability is:
$\displaystyle 1- [{5\choose 0}(\frac{1}{36})^0(1-\frac{1}{36})^{5-0}] = 1- (\frac{35}{36})^5 = \frac{71}{1296}$
Oh, and yeah, it's a binomial.