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Math Help - Probability Poisson Distribution

  1. #1
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    Probability Poisson Distribution

    I just got a question in my exercise book that I tried to attempt but continually got the wrong answer. I am asking here to see if it was my problem or the books. The question is really quite simple:

    Y is distributed as a poisson distribution. When m = 2.7 (mean) find P(X<=4|X>=2)

    I thought it would just be the probability of P(X=2) + P(X=3) + P(X=4) as all events are independent. However, this is not the correct answer.

    I tried to do it using the formula for conditional probability but of course as they are independent this did not work.

    A progression of the solution would be appreciated.

    Cheers
    Qwertyuiop23
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  2. #2
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    What's the correct answer?

    Have you tried  \frac{pr(2\leq X \leq 4)}{pr(X\geq 2)} =\frac{pr(X=2)+pr(X=3)+pr(X=4)}{1-[pr(X=1)+pr(X=0)]}?

    This would make sense to me since pr(C|A)=\frac{pr(A\cap C)}{pr(A)}
    Last edited by downthesun01; May 4th 2010 at 03:14 AM.
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