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Math Help - Normal Distribution - Mean and Standard Deviation

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    Normal Distribution - Mean and Standard Deviation

    How do you work out the mean and standard deviation when you are given Total number of trials and probability of success.

    i.e: Total number of trials = 100
    probability of success = 10% (0.1)
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    Quote Originally Posted by shiiganB View Post
    How do you work out the mean and standard deviation when you are given Total number of trials and probability of success.

    i.e: Total number of trials = 100
    probability of success = 10% (0.1)
    Mean = np
    SD= sqrt(npq) where q = prob of failure = 1-p
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  3. #3
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    Quote Originally Posted by shiiganB View Post
    How do you work out the mean and standard deviation when you are given Total number of trials and probability of success.

    i.e: Total number of trials = 100
    probability of success = 10% (0.1)
    Your question appears to refer to a binomial distribution. Why then do you have normal distribution in your post title?
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