How do you work out the mean and standard deviation when you are given Total number of trials and probability of success. i.e: Total number of trials = 100 probability of success = 10% (0.1)
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Originally Posted by shiiganB How do you work out the mean and standard deviation when you are given Total number of trials and probability of success. i.e: Total number of trials = 100 probability of success = 10% (0.1) Mean = np SD= sqrt(npq) where q = prob of failure = 1-p
Originally Posted by shiiganB How do you work out the mean and standard deviation when you are given Total number of trials and probability of success. i.e: Total number of trials = 100 probability of success = 10% (0.1) Your question appears to refer to a binomial distribution. Why then do you have normal distribution in your post title?
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Originally Posted by shiiganB 
