# independant events

• Apr 22nd 2010, 02:06 AM
npm1
independant events
A={a heart is drawn}
C={a face card is drawn (J,Q,K)}
tis is my workking.... for whether A and C is indepent
P(A intersection C)=3/52=0.0576
(13/52)*(12/52)=0.25*0.23=0.575
whats goin on
• Apr 22nd 2010, 02:22 AM
dkmathguy
Two events, A and C, are independent if the fact that A occurs does not affect the probability of C occurring.

When two events, A and B, are independent, the probability of both occurring is: P(A and B) = P(A) · P(B)

(13/52)(12/52)=(1/4)(12/52)=12/208=6/104=3/52=0.0577?
• Apr 22nd 2010, 02:54 AM
npm1
is dat awsner
rounded up.....
• Apr 22nd 2010, 03:33 AM
mr fantastic
Quote:

Originally Posted by npm1
A={a heart is drawn}
C={a face card is drawn (J,Q,K)}
tis is my workking.... for whether A and C is indepent
P(A intersection C)=3/52=0.0576
(13/52)*(12/52)=0.25*0.23=0.575
whats goin on

'Whats goin on' is that you should have worked with exact values and done the basic arithmetic by hand instead of running to a calculator and getting decimal approximations (clinically proven to cause brain rot).