Competition results

**losm1** · April 19th 2010, 12:12 PM

Competition results:

Result 10 20 30 40 50
Participants 1 2 5 k 3

Mean value of the results is 34. $k=?$

Help?

**cpbrunner** · April 19th 2010, 08:17 PM

If the mean value of the results is 34, then you need to solve the following for $k$ :

$\frac{1(10)+2(20)+5(30)+k(40)+3(50)}{1+2+5+k+3}=34$

**downthesun01** · April 20th 2010, 02:41 AM

The mean is equal to the sum of the results divided by the sum of the competitors, so:

$\frac{10+20+30+40+50}{1+2+5+k+3}=34$

From there, it's simple algebra. Solve for k.

**Debsta** · April 20th 2010, 02:44 AM

Originally Posted by downthesun01

The mean is equal to the sum of the results divided by the sum of the competitors, so:

$\frac{10+20+30+40+50}{1+2+5+k+3}=34$

From there, it's simple algebra. Solve for k.

cpbrunner's got it right. You have to take the frquencies into account on the numerator. downthesun01 hasn't.

**downthesun01** · April 20th 2010, 03:06 AM

My mistake. You're totally right

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