Two pairs [one pair of each two different face values and a card of

a third face value]

Prob(2 pairs) = (13C2 x 4C2 x 4C2 x 11 x 4)/(52C5) = ?

The various terms in above expression arise as follows.

13C2 = (13 choose 2) is the number of ways of choosing the two

different face values for the two pairs.

4C2 = (4 choose 2) is the number of ways of choosing the two suits for

one pair, and the second 4C2 is the number of ways of choosing the two

suits for the second pair.

11 is the number of ways of choosing the face value for the 5th card.

It must not be the same face value as either of the pairs.

4 is the number of ways of choosing the suit for the 5th card.

52C5 = (52 choose 5) is the number of unrestricted ways that 5 cards

can be selected from the 52 in the pack.