P(A+B=4|A=3) = P(B=1|A=3) = 1/6

Given the sum is 4 the (equally likley) possibiliies are (A=1,B=3) (A=2,B=2)b) the first die is 3 given that the sum is 4

(A=3,B=1) so P(A=3|A+B=4) = 1/3

c) the events "the sum is 4" and "the first die is 3" are independent?

d)the sum is 4, given taht the first die is even

e) the first die is even, given taht the sum is 4

How can I approach this? I have a class test tomorrow... thanks so much.