Given E[X]=0.95. Find the probability that X is greater than E[X].
x -1 0 1 2 3
P(X=x) 0.35 0.05 0.1 0.3 0.2
Unsure what's asking me there.
thanks for the help!
Well, exactly what they say, I suppose, i.e. they want to know
$\displaystyle P(X>E[X]){\color{red}=}P(X>0.95)=P(X \in \{1,2,3\})$
$\displaystyle =P(X=1)+P(X=2)+P(X=3)=0.1+0.3+0.2=0.6$.
BTW. It's a bit strange that they tell you what $\displaystyle E[X]$ is, because from the given values and probabilities of X one can easily determine the expected value.