Originally Posted by

**sigma1** wanted to check my answers for this question.

a team played 50 games this year. the results are shown in the table.

before the season started the coach chose a fixture at random to visit the club. what is the probability that the fixture he attended was

a) an away win

b)a match the team did not loose

c)a win given it was a home game

My answers

for a) $\displaystyle \frac{13}{17+13} $ = $\displaystyle \frac {13}{30}$

b) $\displaystyle \frac {17+2+13+5}{17+2+7+13+5+6}$ = $\displaystyle \frac{37}{50}$

c) $\displaystyle \frac {17}{17+2+7}$ = $\displaystyle \frac{17}{26}$