Thread: Probability Question

Hi
Im having trouble with this question:

What is the probability of not throwing 7 or doubles for six consecutive throws with a pair of dice.

I know that for each pair of dice there are 36 possibilities. So the sample space and total number of solutions would be 36^6.
I understand how to get the denominator but not the numerator.

I mean isn't their 6 ways of getting a seven with dice and six ways of getting double?
So i did (12/36)^6 but I end up with 1/729 so since its indirect i do 1 - 1/729. But i still get it wrong.

The final answer is supposed to be 64/729 btw. So how would I go on about doing this?

Thanks in advance

Originally Posted by asemh

Hi
Im having trouble with this question:

What is the probability of not throwing 7 or doubles for six consecutive throws with a pair of dice.

I know that for each pair of dice there are 36 possibilities. So the sample space and total number of solutions would be 36^6.
I understand how to get the denominator but not the numerator.

I mean isn't their 6 ways of getting a seven with dice and six ways of getting double?
So i did (12/36)^6 but I end up with 1/729 so since its indirect i do 1 - 1/729. But i still get it wrong.

The final answer is supposed to be 64/729 btw. So how would I go on about doing this?

Thanks in advance

Probability (not throwing 7 or doubles for one dice roll) = 24/36.

Probability (not throwing 7 or doubles for six dice rolls) = (24/36)^6.