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Math Help - Help Me! :)

  1. #1
    iwz
    iwz is offline
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    Smile Help Me! :)

    Ok.
    The game that goes like this
    (on an rpg.)

    There are two players. And one 6 shot revolver. One bullet is placed randomly in this gun.
    The players take turns to shoot at their feet.
    So for the first player
    his possible odds are 1,6 then 1,4 then 1,2
    the second players odds are 1,5 then 1,3 then 1,1 (he is obviously going to lose if he reaches that)

    Ive already determined that the odds favour the second player.
    Am i correct?

    Is there a way to beat this game and make money?
    I need a betting strategy if possible aswell.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by iwz View Post
    Ok.
    The game that goes like this
    (on an rpg.)

    There are two players. And one 6 shot revolver. One bullet is placed randomly in this gun.
    The players take turns to shoot at their feet.
    So for the first player
    his possible odds are 1,6 then 1,4 then 1,2
    the second players odds are 1,5 then 1,3 then 1,1 (he is obviously going to lose if he reaches that)

    Ive already determined that the odds favour the second player.
    Am i correct?

    Is there a way to beat this game and make money?
    I need a betting strategy if possible aswell.
    Number the chambers 1, 2, 3, .., 6. The bullet is in one of these.

    Player 1 loses is it is in chamber 1, 3, or 5, and player 2 loses if it is
    in chamber 2, 4, or 6. As these are equaly likely there is no advantage
    in favour of either player.

    If however the cylinder is spun before each shot the first player is
    more likely to lose (shoot themselves).

    RonL
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  3. #3
    iwz
    iwz is offline
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    Thanks

    Can you suggest a possible betting strrategy for this.
    ive tried bet raising
    didnt really work :P
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  4. #4
    Junior Member
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    It's ALL about LUCK lol
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  5. #5
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    ofcourse not if the cylinder of the gun spun every time then the first player has a chance of 1.6 but the second will have the chance of 1.5 and then the first one will have a 1.3 and the second one will get a 1.2 then the first one gets a 1.1 and the second one will get the 1
    if its spinned then the odds chance if it dont spin they both get 3chambres wich are alredy chosen to be there chambres 3 is ealge but if its spinned then the first one will havea chance of 1out of 6 but the second time theres not the same chances but there are new chances a chance of 1out of 5 wich is indeed a bigger chance so the second guy is mathicly gonne lose big time

    im realy sorry if my english wasnt correctly its not my forn lanuage and my grammar is terrible

    afther some minutes of thinking ive thoug this migth be wrong since if the cylinder is spun every time this also ables the abilety to hit on the same chamber for example if the first hit hits on chamber 2 and the bullet is in chamber 1 then maybe the second time it will also hit chamber 2 so theres no advantage no way to manipulate this both players have the same chances the only thing wich player 2 has in his favour is that player one has a chance of 1out of six that he shoots himself in the first time and if he does then player 2 doesnt have to shoot himself annymore
    Last edited by 3tyson; November 24th 2008 at 01:01 AM.
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