Originally Posted by icemanfan That's a start. When you multiply it out, you will find that the function is a parabola. Where does the parabola achieve its maximum value? by changing to f(x) = a(x-h)²+k form ?
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Originally Posted by myaa02 by changing to f(x) = a(x-h)²+k form ? Yes, you want to change the equation to that form. Be careful, though. You made a mistake in multiplying it out. The correct equation is .
Originally Posted by icemanfan Yes, you want to change the equation to that form. Be careful, though. You made a mistake in multiplying it out. The correct equation is . how did you get 2000x if you multiply 100x with 80 ? nvm i just got it lol
what do you do after ?
Originally Posted by myaa02 what do you do after ? You should get . Then, observe that the parabola achieves its maximum value at the vertex. What is the vertex of this parabola?
Originally Posted by icemanfan You should get . Then, observe that the parabola achieves its maximum value at the vertex. What is the vertex of this parabola? vertex is -10
Originally Posted by myaa02 vertex is -10 Incorrect. Remember, the vertex is a point. Also, the x-value of the vertex is not -10.
Originally Posted by icemanfan Incorrect. Remember, the vertex is a point. Also, the x-value of the vertex is not -10. i seriously don't know how to get the vertex.
Originally Posted by myaa02 i seriously don't know how to get the vertex. If the equation of the parabola is , then the vertex of the parabola is (h, k).
Originally Posted by icemanfan If the equation of the parabola is , then the vertex of the parabola is (h, k). so its (-10,490000)
Originally Posted by myaa02 so its (-10,490000) The vertex is (10, 490000).
Originally Posted by icemanfan The vertex is (10, 490000). now how am I supposed to find the " new markup " in order to maximize the revenue ?
Originally Posted by myaa02 now how am I supposed to find the " new markup " in order to maximize the revenue ? The function is maximized when x = 10. The markup is 100x, so what should the markup be?
Originally Posted by icemanfan The function is maximized when x = 10. The markup is 100x, so what should the markup be? So, the markup should be 1000 ?
Originally Posted by myaa02 So, the markup should be 1000 ? Yes, that's correct.
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