Aki is a participant
on a trivia-based game show. He has an
equal likelihood on any given trial of being
asked a question from one of six categories:
Hollywood, Strange Places, Number Fun,
Who?, Having a Ball, and Write On! Aki
feels that he has a 50/50 chance of getting
Having a Ball or Strange Places questions
correct, but thinks he has a 90% probability
of getting any of the other questions right. If
Aki has to get two of three questions
correct, what are his odds of winning?
I tried finding all the different combinations and using the probabilities but cannot get the right answer(Headbang)
Thanks. I understand everything you did except the part in , why did you multiply by 3?
Originally Posted by Grandad
This is an example of the Binomial Distribution Formula. The probability of getting successes from trials is:Here, . The probability of getting 2 questions right out of 3 is:
Originally Posted by ibetan
and . This is where the 3 comes from.
It is simply the number of ways of choosing 2 questions out of 3, these being the questions that Aki gets right. He could get:
right, right, wrongor
right, wrong, rightor
wrong, right, right3 ways. Do you see now?