Hi everyone!

I am not sure if this question corresponds to this section, but here we go

I have a table of probabilities in the following way:

Dp a1 a2 a3 a4

453,2 0,75588 0,1474 0,0903 0,0418

523,3 0,72334 0,1372 0,0883 0,045

604,3 0,68883 0,1278 0,0854 0,0475

697,3 0,65272 0,1194 0,0821 0,0491

805,8 0,61545 0,1121 0,0789 0,05

So that for each diameter Dp, htere is a probability of having a1, a2, a3 and so on, and the sum of all these probabilities for each Dp is 1 (maybe in the expample this doesnīt occurs since I didnīt show all the values)

That is: a1(dp1) + a2(dp1) + a3(dp1) + a4(dp1) = 1

a1(dp2) + a2(dp2) + a3(dp2) + a4(dp2) = 1

......

But I need to know, form a mix of several diameters how many of them of each kind $\displaystyle a_i$ would be. For example, for a sample of diameters Dp1 and Dp2, where:

Dp1 + Dp2= N,

can I know from the previous percentajes how many of a1(Dp1) and a1(Dp2) would it be in the total?

I had tried by doing

Dp1 * a1(Dp1) = N1

Dp2 * a1(Dp2) = N2

but since a1(Dp1)+a1(Dp2) $\displaystyle !=$1 , then N1+N2 $\displaystyle !=$N

Thanks in advance!!