So that for each diameter Dp, htere is a probability of having a1, a2, a3 and so on, and the sum of all these probabilities for each Dp is 1 (maybe in the expample this doesnīt occurs since I didnīt show all the values)
But I need to know, form a mix of several diameters how many of them of each kind would be. For example, for a sample of diameters Dp1 and Dp2, where:
Dp1 + Dp2= N,
can I know from the previous percentajes how many of a1(Dp1) and a1(Dp2) would it be in the total?
I had tried by doing
Dp1 * a1(Dp1) = N1
Dp2 * a1(Dp2) = N2