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Math Help - Meeting at Coffee Shop

  1. #1
    lpd
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    Meeting at Coffee Shop

    Hi, can some one help me with this problem?

    Two people A and B will be arriving at a small coffee shop at any time between 8am and 9am equally likely. Each of them will stay exactly 10 minutes in the bar. What is the probability that they will meet each other in the shop?

    Thanks
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  2. #2
    Member Awsom Guy's Avatar
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    There are 60 min in an hour so 10 min of 1 hour is 10/60.
    simplify and you get 1/6. Bang your answer...
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  3. #3
    lpd
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    Can i say this then?

    P(A) = person A's ratio (minutes stay : total possible minutes) = 10/60 = 1/6
    P(B) = person B's ratio (minutes stay : total possible minutes) = 10/60 = 1/6
    P(A and B) = probability that both of them are there = ?

    ...P(A and B) = P(A) x P(B)
    ...P(A and B) = (1/6)*(1/6)

    ...P(A and B) = 1/36
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  4. #4
    Flow Master
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    Quote Originally Posted by lpd View Post
    Hi, can some one help me with this problem?

    Two people A and B will be arriving at a small coffee shop at any time between 8am and 9am equally likely. Each of them will stay exactly 10 minutes in the bar. What is the probability that they will meet each other in the shop?

    Thanks
    Read these threads:

    http://www.mathhelpforum.com/math-he...obability.html

    http://www.mathhelpforum.com/math-he...g-problem.html

    Quote Originally Posted by Awsom Guy View Post
    There are 60 min in an hour so 10 min of 1 hour is 10/60.
    simplify and you get 1/6. Bang your answer...
    This is not correct.
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