Thread: Meeting at Coffee Shop

Hi, can some one help me with this problem?

Two people A and B will be arriving at a small coffee shop at any time between 8am and 9am equally likely. Each of them will stay exactly 10 minutes in the bar. What is the probability that they will meet each other in the shop?

Thanks

There are 60 min in an hour so 10 min of 1 hour is 10/60.
simplify and you get 1/6. Bang your answer...

Can i say this then?

P(A) = person A's ratio (minutes stay : total possible minutes) = 10/60 = 1/6
P(B) = person B's ratio (minutes stay : total possible minutes) = 10/60 = 1/6
P(A and B) = probability that both of them are there = ?

...P(A and B) = P(A) x P(B)
...P(A and B) = (1/6)*(1/6)

...P(A and B) = 1/36

Originally Posted by lpd

Hi, can some one help me with this problem?

Two people A and B will be arriving at a small coffee shop at any time between 8am and 9am equally likely. Each of them will stay exactly 10 minutes in the bar. What is the probability that they will meet each other in the shop?

Thanks

Read these threads:

http://www.mathhelpforum.com/math-he...obability.html

http://www.mathhelpforum.com/math-he...g-problem.html

Originally Posted by Awsom Guy

There are 60 min in an hour so 10 min of 1 hour is 10/60.
simplify and you get 1/6. Bang your answer...

This is not correct.