Results 1 to 3 of 3

Math Help - Conditional probability and independence

  1. #1
    Newbie
    Joined
    Feb 2010
    Posts
    11

    Conditional probability and independence

    A product can have three kinds of defects: A, B, C. It is rejected if  (A \cap B) \cup C.
    It is known that P(A) = 0.15 , P(B) = 0.25 , P(C) = 0.30.
    It is also known that P(A|C) = 1.3\cdot P(A) and P(B|C) = 2\cdot P(B).
    Also A and B are independent.

    What is  P[(A \cap B) \cup C] ?

    Some one can help me with this?

    Thanks in advance
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member
    Joined
    Jan 2010
    Posts
    65
    Quote Originally Posted by johanS View Post
    A product can have three kinds of defects: A, B, C. It is rejected if  (A \cap B) \cup C.
    It is known that P(A) = 0.15 , P(B) = 0.25 , P(C) = 0.30.
    It is also known that P(A|C) = 1.3\cdot P(A) and P(B|C) = 2\cdot P(B).
    Also A and B are independent.

    What is  P[(A \cap B) \cup C] ?

    Some one can help me with this?

    Thanks in advance
    I don't see it right now but to get you started, you can find (A \cap B) easily because they are independent. So it is just P(A)P(B). You know P(C) So you are left to find P(A\cap B\cap C)

    Using the conditional probabilities you can find P(A\cap C) and P(B\cap C)

    Try to mess with these and see what you can do.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Feb 2010
    Posts
    11
    Quote Originally Posted by jass10816 View Post
    I don't see it right now but to get you started, you can find (A \cap B) easily because they are independent. So it is just P(A)P(B). You know P(C) So you are left to find P(A\cap B\cap C)

    Using the conditional probabilities you can find P(A\cap C) and P(B\cap C)

    Try to mess with these and see what you can do.
    P(A\cap B\cap C) is exactly my problem
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Conditional Probability Independence Proof
    Posted in the Advanced Statistics Forum
    Replies: 5
    Last Post: October 19th 2011, 10:05 AM
  2. conditional probability/independence
    Posted in the Statistics Forum
    Replies: 1
    Last Post: March 28th 2010, 06:02 AM
  3. Replies: 1
    Last Post: January 26th 2010, 12:43 AM
  4. Conditional Probability and Independence
    Posted in the Advanced Statistics Forum
    Replies: 1
    Last Post: September 29th 2008, 10:09 PM
  5. Conditional Probability and Independence
    Posted in the Statistics Forum
    Replies: 1
    Last Post: June 24th 2008, 07:34 PM

Search Tags


/mathhelpforum @mathhelpforum