(a) Two temperatures are in the ratio 16:13. If the second temperature is 169C, what is the first temperature?

(b) Two speeds are in the ratio 8:3. If the first speed is 320Km/h,what is the second speed?

please show working out thanks(Hi)(Hi)

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- Mar 8th 2010, 08:00 AMtinagreg13ratio and proportion
(a) Two temperatures are in the ratio 16:13. If the second temperature is 169C, what is the first temperature?

(b) Two speeds are in the ratio 8:3. If the first speed is 320Km/h,what is the second speed?

please show working out thanks(Hi)(Hi) - Mar 8th 2010, 09:34 AMQuacky
$\displaystyle 16:13 = y:169$

Remember that whatever you multiply one side of the ratio by, you must multiply the other side by the same number.

$\displaystyle 169\div13=13$, So

$\displaystyle y=16\times13=208$

Because both sides of the ratio have to be multiplied by $\displaystyle 13$ to get from $\displaystyle 13$ in ratio 1 to $\displaystyle 169$ in ratio 2.

$\displaystyle 16:13=208:169$

Answer: $\displaystyle 208$

Have an attempt at the second part yourself (Wink)