C(14,7)*c(7,5)=?
Hey,
Fourteen construction workers are to be assigned to three different tasks. Seven workers are needed for mixing cement, five for laying bricks, and two for carrying the bricks to the brick layers. In how many different ways can the workers be assigned to these tasks?
I have the answer:
72,072
but I don't know how to get it. Thanks to anyone who can help.
Hello, Averee!
A different approach . . . same answer.
Fourteen construction workers are to be assigned to three different tasks.
Seven workers are needed for mixing cement, five for laying bricks,
and two for carrying the bricks to the brick layers.
In how many different ways can the workers be assigned to these tasks?
This is a "partitioning" of 14 people into groups of 7, 5 and 2.
. . . . . . . . . . . . . . . . . . . 14!
The number of ways is: . --------- . = . 72,072
. . . . . . . . . . . . . . . . . .7! 5! 2!