I was just confused if I am thinking this one right.

so the question is:

"In a set of numbers from 1 to 10. If two numbers are to be selected from these 10 numbers with replacement, then what is the probability that at least one of them is even?"

So I thought. there are four possible outcome,

Even*Odd

Odd*Even

Odd*Odd

Even*Even

and since 3 out of them contains even number So I thought the probability

was 3/4. Is this the right way of thinking this problem??

please help. thank you.