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**thereddevils** In a large factory with many workers , 30 % of the workers belong to union A , 60 % Union B and the remaining 10 % doesn't join any union . A sample of 5 workers is selected .

(1) Find the probability that the sample has less than 2 members of UNion A .

(2) It's found that exactly 4 of these workers are members of union . What is the probability that more of the members come from Union A than UNion B .

so For (1) ,

it could be 1 member from A , then 4 from A' OR 0 from A and 5 from A'

P(x<2)=(0.3)(0.7)^4+(0.7)^5=0.2401

(2) I did not consider the one member who has no union because it doesn't make a difference so Union A - 4 , B - 0 , OR A-3 , B-1

P(A>B)=(0.3)^4+(0.3)^3(0.6)=0.0243

But unfortunately both are wrong . The answer given is (1) 0.528 (2) 1/9