The probability a girl wears spectacles is 1/12 and the probability a student who wears spectacles is a girl is 1/9 . The probability that a student selected randomly is not a girl and does not wear spectacles is 3/4 . What is the probability that another person chosen randomly is a girl who wears spectacles ?
Let S=spectacles and G=girl
P(G n S)=1/12
P(G' n S')=3/4
and the question is asking for P(G n S) again ??
here's an alternative way, a bit long though.
of the all the girls wear spectacles.
of the students who wear spectacles are girls.
of the students are boys who don't wear spectacles.
We are not directly given
...the fraction of all the students that are girls.
The word "another" may be offputting.
The following calculation finds the fraction of students that are girls who wear spectacles.
The question doesn't state that a person was chosen before another. It only gives another probability.
E....girls who don't wear spectacles
F....girls who do
C....boys who don't
D....boys who do
The total number of students are E+F+C+D=B+G