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Math Help - Mutually exclusive?

  1. #1
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    Mutually exclusive?

    P(A)- 1/2
    P(A|B)- 1/3
    P(B|A) - 1/2

    I don't think they are independant considering event B changes the probablity of event A occuring. what I can't figure out is P(B) or P(A or B), last P(A and B). Any input is appreciated.

    I think the P(A and B) is (1/2)(1/2)= 1/4, if you could tell me if thats wrong why you would make my day.
    Last edited by GideonSD; February 16th 2010 at 02:42 PM.
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  2. #2
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    Quote Originally Posted by GideonSD View Post
    P(A)- 1/2
    P(A|B)- 1/3
    P(B|A) - 1/2

    I don't think they are independant considering event B changes the probablity of event A occuring. what I can't figure out is P(B) or P(A or B), last P(A and B). Any input is appreciated.
    P(B|A)=\frac{P(A\cap B)}{P(A)} implies that P(A\cap B)=\frac{1}{4}.

    Moreover, P(B)=\frac{P(A\cap B)}{P(A|B)}
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