Having trouble working out the following problem for my son. Two cards are randomly selcted from a standard 52 card deck. What is the probability of getting two hearts or two cards less than four( aces count as 1)?

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- Feb 14th 2010, 12:57 PMLArchambeau3Basic Probality?
Having trouble working out the following problem for my son. Two cards are randomly selcted from a standard 52 card deck. What is the probability of getting two hearts or two cards less than four( aces count as 1)?

- Feb 14th 2010, 01:53 PMANDS!
Basic probability goes like this: # Of Successes/# Of Outcomes. In a 52 card deck, there are 52 possible cards (outcomes) you can select. How many of those cards are hearts? How many of those cards are less than (but not equal to) four. How many of those cards are both less than four AND hearts?

The probability of getting two hearts OR two cards less than four is P(Two Hearts) + P(Less Than Four) - P(Two Hearts AND Less Than Four).

See if you can suss out the problem now, and see if you get why why subtract that last probability from the combination of the two. - Feb 14th 2010, 04:40 PMLArchambeau3thanks ANDS
I had the first part but the subtraction of the "AND" probability was eluding me. I understand the the subtraction removes the over lap. Thank you.