A six-sided die is weighted so that the probability of rolling a 1 is twice the probability of rolling any other number. what is the probability that the sum of two numbers thrown in two tries is equal to 4?
here is how far i got:
we are looking for the probability of rolling (3,1) (2,2) or (1,3) with this die.
Probability of rolling a 1 is 2/7 and probability of rolling any other number is 1/7
I do not know how to finish the problem from here.