Hello, Grey!

The answer of 50% is much too easy.

. . It is a classic trick question.

There areIn a box, I have a ball, which has an unknown colour (can be either red or blue).

I put in another ball, which is red, shake the box and take out a random ball.

The ball taken out turns out to be red.

If I take out the another ball, what is the chance of drawing a red ball?fourequally likely outcomes.

(A) The box contains a red ball, call it R1.

. . .A red ball is added, call it R2.

. . .(1) We draw R1, then we draw R2.

. . .(2) We draw R2, then we draw R1.

(B) The box contains a blue ball, call it B1.

. . .A red ball is added, call it R2.

. . .(3) We draw R2, then we draw B1.

. . .(4) We draw B1, then we draw R2.

We are told that the first ball is red.

. . Hence, case (4) is discarded.

We have three equally likely outcomes:

. . (1) We draw R1, then we draw R2.

. . (2) We draw R2, then we draw R1.

. . (3) We draw R2, then we draw B1.

Intwo of the threeoutcomes, the second ball is red.

Therefore: .P(second ball is red) .= .2/3

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This is identical to another classic.

I know my neighbor has two children.

I meet one of them and the child is a girl.

What is the probability that the other child is a girl?

The "obvious" answer is 50%; the child must be a boy or a girl, right?

. .Wrong!

There arethreepossible cases.

He has one girl, one boy.

. . .(1) You met the girl; the other is a boy.

He has two girls: G1 and G2.

. . (2) You met G1; the other is G2.

. . (3) You met G2; the other is G1.

Intwo of the threecases, the other child is a girl.