1. In a game of chance each player throws two unbiased dice and scores the difference of the two numbers shown on the dice. two players compete in the game. one wins if he scores at least 4 or more than his opponent. find the probability that neither wins.

The possible scores for a throw are {5,4,3,2,1,0}

Combinations of scores to win are (5,1); (4,0); (5,0).

P(score 5)=1/36

P(score 4)=2/36

P(score 1)=5/36

P(score 0)=6/36

P(score difference greater than 4)=

P(neither wins, i.e. score difference less than 4)=

answer is supposed to be 0.914, I can't find anywhere i have gone wrong, so i need someone to help me see if i have.