Thread: probability of selection

Hi guys, i am taking statistics and just wondering if im doing this right.
A system can have 3 different types of defects.
*U*=intersection

P(A)=.12 P(B)=.07 P(C)=.05
P(A U B)=.13 P(B U C)=.10 P(A U C)=.1
P(A *U* B *U* C)=.01

1. Probability system doesnt have type A defect:
1-.12=.88

2. Probability it has both A and B defects:
P(A U B)= .13

3. Probability of A and B but not C

P(A U B)-P(C)= .13 -.05=.8

4. Probability that the system has at most two of these defects?
This question im stuck on and not sure how to figure out.

Thanks guys, since im already here ill go help someone out with something i know about.

Originally Posted by netring

Hi guys, i am taking statistics and just wondering if im doing this right.
A system can have 3 different types of defects.
*U*=intersection

P(A)=.12 P(B)=.07 P(C)=.05
P(A U B)=.13 P(B U C)=.10 P(A U C)=.1
P(A *U* B *U* C)=.01


2. Probability it has both A and B defects:
P(A U B)= .13

CB

Originally Posted by netring

Hi guys, i am taking statistics and just wondering if im doing this right.
A system can have 3 different types of defects.
*U*=intersection

P(A)=.12 P(B)=.07 P(C)=.05
P(A U B)=.13 P(B U C)=.10 P(A U C)=.1
P(A *U* B *U* C)=.01



3. Probability of A and B but not C

P(A U B)-P(C)= .13 -.05=.8

CB

Originally Posted by netring

Hi guys, i am taking statistics and just wondering if im doing this right.
A system can have 3 different types of defects.
*U*=intersection

P(A)=.12 P(B)=.07 P(C)=.05
P(A U B)=.13 P(B U C)=.10 P(A U C)=.1
P(A *U* B *U* C)=.01


4. Probability that the system has at most two of these defects?
This question im stuck on and not sure how to figure out.

CB

thanks!