2 gamblers bet $1 each on the successive tosses of a coin. each as $6. what is the probability that
a. they break even after 6 tosses?
b. one player wins all the money on the tenth toss?
a. since there are 6 tosses and equal probability of a head and tail,
the ans should be 6 x (0.5)^6
b. in order to win all the money o the other player, he needs to win 8 games and loss 2 games, where the 10th toss have to be a win.
so, (9 choose 7) x ( 0.5)^10
but i didnt get the answer :(