A gambler has been dealt with 5 cards: 2 aces, 1 king, 1 five and 1 nine. he discards the 5 and 9 and takes 2 more cards. what is the probability that he ends with a full house?

my working:

to get a full house: its either

3 aces and 2 kings or 2 aces and 3 kings

P ( 3 aces and 2 kings ) = 2/47 x 3 /46 x 2

p (2 aces and 3 kings ) = 2/47 x 3 /46

so i think the answer should be the sum of both...but the answer given was 0.0083..