A tennis player finds that on average he gets his serve in eight out of every ten attempts. He serves an ace once every fifteen serves. He serves four times.
Assuming that successive serves are independent events find the probability that he hits exactly three aces and the other serve lands in.
My approach was:
1) All serves in =
2) 3 aces =
Multiply the 2 results = 0.000453
However the solutions have 0.000869
May I ask where is it that I'm going wrong
TIA for any feedback