Can you use a calculator? And there is only one question here.
1. A gardener plants beetroot seeds. The probability of a see dnot germinating is 0.35, independently for each seed.
Find the probability that, in a row of 40 seeds, the number not germinating is:
a) nine or fewer
b)seven or more
c)equal to the number germinating
Well not use a calculator in the sense that you can do "2*3" and get the answer, I mean set up the problem, and use the binomial function on a TI-83 to number crunch. If not then you need to use the formula for the Binomial Distribution to calculate P(X less than or equal to 9), which means P(0)+P(1). . .+P(9), and the P(7 or more) can be done by taking the compliment of P(less than 7).
The last one is easy. The only way way the number germaning can be the same as the number not germaning is if they are both equal. There is only one number that satisfies that, and you can plug and chug that one right in.
What exactly about this problem is giving you pause?