Question: A die has 6 sides numbered 1-6. If 3 dices are thrown, what is the probability that at least one of the dices shows the number six?
For this question, do I have to take into consideration that the other two dices are not sixes? This is what I get:
1/6 for first die to be a 6
(5/6)*(1/6) for second die to be a 6 if the first is not
(25/36)*(1/6) for the third die to be a 6 if the first two are not
adding them up I get 91/216
Is my analysis correct?