Question: A die has 6 sides numbered 1-6. If 3 dices are thrown, what is the probability that at least one of the dices shows the number six?

For this question, do I have to take into consideration that the other two dices are not sixes? This is what I get:

1/6 for first die to be a 6

(5/6)*(1/6) for second die to be a 6 if the first is not

(25/36)*(1/6) for the third die to be a 6 if the first two are not

adding them up I get 91/216

Is my analysis correct?