Sorry, I was having difficulty with the equation editor on here. I've attached my problem as a picture file.
I need to show that the two equations are equal, and I'm not sure where to begin.
Thanks!
Assuming that $\displaystyle \overline{z}$ is the conjugate of the complex number $\displaystyle z$, that statement is false.
$\displaystyle \overline{({z-\overline{z}})^2~}=\overline{z~}^2 -2\overline{z}z+z^2 $.
Note that $\displaystyle \overline{\overline{z}}=z $ and $\displaystyle \overline{z^2}=\overline{z}^2 $