The Bridge club has 8 boys and 3 girls. Four players are randomly selected to play at one table. A) what is the probability of a table with 2 boys and 2 girls? B) what i the probability of a table with atleast 2 girls?
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Originally Posted by needuhelp The Bridge club has 8 boys and 3 girls. Four players are randomly selected to play at one table. A) what is the probability of a table with 2 boys and 2 girls? B) what i the probability of a table with atleast 2 girls? A) $\displaystyle \frac{{8 \choose 2} \cdot {3 \choose 2}}{{11 \choose 4}}$. B) At least two girls means either 2 girls and 2 boys or 3 girls and 1 boy or 4 girls and 0 boys. Calcultae each probability (use part A) as a guide) and then add them up.
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